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Matters and Properties of Matters
Atomic Structure with Examples
Periodic Table
The Mole Concept with Examples
Gases with Examples
Chemical Reactions with Examples
Nuclear Chemistry (Radioactivity)
Acids and Bases
Rates of Reactions (Chemical Kinetics)
Chemical Equilibrium
Chemical Bonds
Exams and Problem Solutions
--Matters and Properties of Matters Exams and Problem Solutions
--Atomic Structure Exams and Problem Solutions
--Periodic Table Exams and Problem Solutions
--The Mole Concept Exams and Problem Solutions
--Gases Exams and Problem Solutions
--Chemical Reactions Exams and Problem Solutions
--Nuclear Chemistry (Radioactivity) Exams and Problem Solutions
--Solutions Exams and Problem Solutions
--Solutions Exam1 and Problem Solutions
--Solutions Exam2 and Problem Solutions
--Solutions Exam3 and Problem Solutions
--Acids and Bases Exams and Problem Solutions
--Thermochemistry Exams and Problem Solutions
--Rates of Reaction Exams and Problem Solutions
--Chemical Equilibrium Exams and Problem Solutions
--Chemical Bonds Exams and Problem Solutions
Old Version


Solutions Exam1 and Problem Solutions

Solutions Exam1 and  Problem Solutions

1. X solid has ionic structure and solubility of it increases with increasing temperature. If solubility of X in water at 15 0C is 20g X/100 g water, find which ones of the following statements are true for solution prepared by using 10 g X and 50 g water at 15 0C;

I. This solution conducts electric current

II. If 30 g water and 5 g X are added to solution under constant temperature, some amount of X stays undissolved.

III. If solution is cooled from 15 0C to 10 0C, some amount of  crystallize.


I. Since structure of X is ionic, when it dissolves in water it decompose into its ions and we know that solutions including ions conduct electric current. I is true.

II. After addition of water and X we have;

Mass of water=50+30=80 g

Mass of X=10+5=15 g

At 15 0C;

100g water dissolves 20 g X

80g water dissolves ? g X


?=16 g X can be dissolved in 80 g water. Since we have 15 X, solution is unsaturated, so all X is dissolved. II is false.

III. At 15 0C;

100 g water dissolves 20 g X

50 g water dissolves ? g X


?=10 g X can be dissolved.

This solution is saturated. Thus, since it is endothermic solution ( solubility increases with increasing temperature), when we cool it some X crystallize. III is true.

2. There are equal amounts of water in given containers.

Find relation between solubility of CO2 gas in water under given conditions.


Solubility of CO2 in water increases with increasing partial pressure of CO2 and decreasing in the temperature. I and II has equal temperature but partial pressure of CO2 in II is larger than I. So, solubility of II is larger than I.

I and III has equal partial pressure, but temperature of I is lower than III, so solubility of I is larger than III.Relation between them become;

II > I > III

3. Graph given below shows relation between solubility and temperature of X and Y solids.

Which one of the following statements are false for this graph?

I. Dissolution of X in water is exothermic

II. When X solid and X-water solution in equilibrium is heated, amount of solid X decreases

III. When saturated Y solution is heated, it becomes unsaturated.


I. Since solubility of X decreases with increasing temperature, it is exothermic. I is true.

II. Since solution of X in water is exothermic, when solution is heated, some amount of X crystallize so amount of X solid increases. II is false.

III. As you can see from the graph, solubility of Y in water is endothermic. Increasing temperature increases its solubility and saturated solution becomes unsaturated. III is true.

4.25 g salt and 125 g water are mixed and solution is prepared. Find concentration of solution by percent mass.


Mass of Solute: 25 g

Mass of Solution: 25 + 125 = 150 g

125 g solution includes 25 g solute

100 g solution includes X g solute


X=20 g %

Or using formula;

Percent by mass=25.100/125=20 %

5. How much water must be vaporized from 0,4 molar 200 mL H2SO4 solution to make it 1,6 molar at same temperature?


V=200 mL = 0,2 L

Mole of H2SO4;


n=M.V, M=n/V

1,6 molar=0,08/V=0,05L=50mL

200-50=150mL water must be vaporized.

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Tags: Matters and Properties of Matters |  Solubility and Factors Affecting Solubility |  Concentration with Examples |  Solutions Exam2 and Problem Solutions |  Solutions Exam3 and Problem Solutions | 

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