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Matters and Properties of Matters
Atomic Structure with Examples
Periodic Table
The Mole Concept with Examples
Gases with Examples
Chemical Reactions with Examples
Nuclear Chemistry (Radioactivity)
Acids and Bases
Rates of Reactions (Chemical Kinetics)
Chemical Equilibrium
Chemical Bonds
Exams and Problem Solutions
--Matters and Properties of Matters Exams and Problem Solutions
--Atomic Structure Exams and Problem Solutions
--Periodic Table Exams and Problem Solutions
--The Mole Concept Exams and Problem Solutions
--Gases Exams and Problem Solutions
--Gases Exam1 and Problem Solutions
--Gases Exam2 and Problem Solutions
--Gases Exam3 and Problem Solutions
--Gases Exam4 and Problem Solutions
--Chemical Reactions Exams and Problem Solutions
--Nuclear Chemistry (Radioactivity) Exams and Problem Solutions
--Solutions Exams and Problem Solutions
--Acids and Bases Exams and Problem Solutions
--Thermochemistry Exams and Problem Solutions
--Rates of Reaction Exams and Problem Solutions
--Chemical Equilibrium Exams and Problem Solutions
--Chemical Bonds Exams and Problem Solutions
Old Version


Gases Exam3 and Problem Solutions

Gases Exam3 and  Problem Solutions

1. Find volume of 0,5mol CH4 under 3,28 atm pressure and 400 0K temperature.


P=3,28 atm, n=0,5mol, T=400 0K, R=0,082, V=?

We use ideal gas law;



V=5 liters

2. If 6,4 g CH4 has pressure 0,5 atm and volume 2 liters, find pressure of 9 g C2H6 having 1 liter volume under constant temperature.(C=12, H=1)


We first find mole of given matters;



Since temperature is constant we write ideal gas law as given below;


P2=0,75 atm

or P2= 57 cm Hg

3. Find density of O2 under 27 0C temperature and 1,23 atm pressure. (O=16)


T=27 + 273=300 0K

If we write ideal gas law for density, we get following equation;


where M is molar mass of O2.



4. If we open the taps given in the picture below, find final temperature of gases.


We use following equation to find final pressure of gas mixture;

P1.V1 + P2.V2 + P3.V3 = Pfinal.Vfinal

3.2 + 4.3 + 0.5 =Pfinal.(2+3+5)

6 + 12=Pfinall.10

Pfinal=1,8 atm

5. When we open the taps given in the picture below, find changes in the pressures of gases.


We should find final pressure of system to make comparison.

P1.V1 + P2.V2 + P3.V3 = Pfinal.Vfinal

P.V + 2P.2V + 3P.V = Pfinal.(V+2V+V)



I. Pressure of first container increase

II. Pressure of second container stays constant

III. Pressure of third container decreases

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Tags: Gases Exam2 and Problem Solutions | 

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